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X^2=-10X-29
We move all terms to the left:
X^2-(-10X-29)=0
We get rid of parentheses
X^2+10X+29=0
a = 1; b = 10; c = +29;
Δ = b2-4ac
Δ = 102-4·1·29
Δ = -16
Delta is less than zero, so there is no solution for the equation
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